Retrieving user information in a Spring Security application is essential for many functionalities such as personalizing user experiences, auditing, and logging activities. This tutorial will guide you through setting up a Spring Boot 3.2 application with Spring Security 6.1 and demonstrating how to retrieve authenticated user information.
Prerequisites
- JDK 17 or later
- Maven or Gradle
- IDE (IntelliJ IDEA, Eclipse, etc.)
Step 1: Set Up a Spring Boot Project
1.1 Create a New Spring Boot Project
Use Spring Initializr to create a new project with the following dependencies:
- Spring Web
- Spring Security
- Thymeleaf (optional, for the frontend)
Download and unzip the project, then open it in your IDE.
1.2 Configure application.properties
Set up the application properties for your project. This file is located in the src/main/resources directory.
# src/main/resources/application.properties
# Server port
server.port=8080
# Thymeleaf configuration (optional)
spring.thymeleaf.cache=false
Step 2: Configure Spring Security
2.1 Create a Security Configuration Class
Create a configuration class to set up Spring Security.
package com.example.demo.config;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.core.userdetails.User;
import org.springframework.security.core.userdetails.UserDetails;
import org.springframework.security.core.userdetails.UserDetailsService;
import org.springframework.security.provisioning.InMemoryUserDetailsManager;
import org.springframework.security.web.SecurityFilterChain;
@Configuration
public class SecurityConfig {
@Bean
public SecurityFilterChain securityFilterChain(HttpSecurity http) throws Exception {
http
.authorizeHttpRequests(authorizeRequests ->
authorizeRequests
.requestMatchers("/login", "/resources/**").permitAll()
.anyRequest().authenticated()
)
.formLogin(formLogin ->
formLogin
.loginPage("/login")
.permitAll()
)
.logout(logout ->
logout
.logoutUrl("/logout")
.logoutSuccessUrl("/login?logout")
.permitAll()
);
return http.build();
}
@Bean
public UserDetailsService userDetailsService() {
UserDetails user = User.builder()
.username("user")
.password("{noop}password")
.roles("USER")
.build();
UserDetails admin = User.builder()
.username("admin")
.password("{noop}admin")
.roles("ADMIN")
.build();
return new InMemoryUserDetailsManager(user, admin);
}
}
Explanation:
SecurityFilterChain: Configures the security filter chain.authorizeHttpRequests: Defines URL authorization.formLogin: Configures form-based login.logout: Configures logout functionality.UserDetailsService: Provides user details for authentication. Here, an in-memory user store is used.
Step 3: Create the Login and Home Pages
3.1 Create the Login Page
Create a login page using Thymeleaf. Create a file named login.html in the src/main/resources/templates directory.
<!DOCTYPE html>
<html xmlns:th="http://www.thymeleaf.org">
<head>
<title>Login</title>
</head>
<body>
<h1>Login</h1>
<form th:action="@{/login}" method="post">
<div>
<label>Username:</label>
<input type="text" name="username"/>
</div>
<div>
<label>Password:</label>
<input type="password" name="password"/>
</div>
<div>
<button type="submit">Login</button>
</div>
</form>
<div th:if="${param.logout}">
You have been logged out.
</div>
<div th:if="${param.error}">
Invalid username or password.
</div>
</body>
</html>
3.2 Create the Home Page
Create a home page that will be accessible only to authenticated users. Create a file named home.html in the src/main/resources/templates directory.
<!DOCTYPE html>
<html xmlns:th="http://www.thymeleaf.org">
<head>
<title>Home</title>
</head>
<body>
<h1>Welcome, <span th:text="${userDetails.username}">User</span>!</h1>
<p>Your roles: <span th:text="${userDetails.authorities}"></span></p>
<a th:href="@{/logout}">Logout</a>
</body>
</html>
Step 4: Create a Controller
4.1 Create the HomeController
Create a controller to handle requests to the login and home pages and to retrieve the authenticated user's information.
package com.example.demo.controller;
import org.springframework.security.core.annotation.AuthenticationPrincipal;
import org.springframework.security.core.userdetails.UserDetails;
import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.web.bind.annotation.GetMapping;
@Controller
public class HomeController {
@GetMapping("/login")
public String login() {
return "login";
}
@GetMapping("/")
public String home(@AuthenticationPrincipal UserDetails userDetails, Model model) {
model.addAttribute("userDetails", userDetails);
return "home";
}
}
Explanation:
@Controller: Marks the class as a web controller.@GetMapping("/login"): Maps GET requests for the login page.@GetMapping("/"): Maps GET requests for the home page.@AuthenticationPrincipal: Injects the currently authenticatedUserDetailsobject.Model: Used to pass attributes to the view.
Step 5: Running and Testing the Application
5.1 Run the Application
Run the Spring Boot application using your IDE or the command line:
./mvnw spring-boot:run
5.2 Test the Login and User Information Retrieval
- Open a web browser and navigate to
http://localhost:8080. - You will be redirected to the login page.
- Enter the username
userand passwordpassword, and click the "Login" button. - You should be redirected to the home page and see a welcome message with the username and roles displayed.
Conclusion
In this tutorial, you have learned how to retrieve user information using Spring Security 6.1 in a Spring Boot 3.2 application. We covered:
- Setting up a Spring Boot project with Spring Security.
- Configuring Spring Security to handle login and user information retrieval.
- Creating login and home pages using Thymeleaf.
- Creating a controller to handle requests and retrieve authenticated user information.
By following these steps, you can effectively manage and retrieve user information in your Spring Boot applications using Spring Security.
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